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MIS Algorithm: From Biological Inspiration to Computation

Explore how the fruit fly's SOP selection inspires efficient distributed Maximal Independent Set (MIS) algorithms for wireless networks and processors.

#mis-algorithm#distributed-systems#biology-inspired-computing#maximal-independent-set#symmetry-breaking#algorithm-complexity#wireless-networks
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Maximal Independent Set (MIS): From Biology to Computation

Presenters: Leen Hassan, Yaman Dahle

A minimalist scientific illustration showing a fruit fly (Drosophila) on the left connected by a smooth line to a computer network graph on the right, symbolizing the connection between biology and algorithms, white background, high quality
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Presentation Roadmap

1
Define the MIS Problem
2
Explore Biological Inspiration
3
Present the Formal Algorithm
4
Prove Correctness (Lemmas)
5
Analyze Complexity
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Why MIS Matters?

• It creates a 'backbone' for wireless networks.
• Essential for efficient message routing.
• Allows clustering: selecting local leaders without a central authority.
• Vital for scalable ad-hoc sensor networks.
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Informal Problem Definition

The Setting: A Distributed System
• Processors solve a task jointly without global knowledge.
• Communication is strictly local (immediate neighbors only).

The Goal: A Maximal Independent Set (MIS)
Select a subset of processors such that:
1. Independence: No two neighboring processors are selected.
2. Dominance: Every processor is either selected or adjacent to a selected one.
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Formal Definition of MIS

Given a Graph G = (V, E), a subset A ⊆ V is a Maximal Independent Set if:

1. ∀ u, v ∈ A, (u, v) ∉ E
(No two nodes in A are neighbors)

2. ∀ v ∉ A, ∃ u ∈ A s.t. (u, v) ∈ E
(Every node outside A has a neighbor in A)
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The Greedy Algorithm Approach

How it works (Sequential)

1. Pick an arbitrary node.
2. Add it to the Independent Set.
3. Remove it and all its neighbors.
4. Repeat until the graph is empty.

! The Challenge

In a distributed system, we lack global knowledge.
Nodes cannot see the whole graph to "pick" sequentially.
We need a local, parallel strategy.
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Luby’s Algorithm (1986)

1 The Algorithm

• Each node chooses a random priority.
• A node joins the MIS if its priority is higher than all its neighbors’.
• All neighbors of a selected node become inactive.
• Repeat on the remaining nodes.

Key Properties

Randomness breaks symmetry.
• Terminates in O(log n) rounds with high probability.
• Correct and efficient in distributed networks.
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Why is Distributed MIS Hard?

The Challenge: Symmetry Breaking

  • In a distributed system, identical nodes lack a central coordinator.
  • If they all act at once, they collide. If they all wait, they deadlock.
  • They cannot simply "take turns" without communication.

The Solution: Randomization

  • Nodes determine their actions by flipping a coin.
  • Randomization breaks the symmetry naturally.
  • It allows fast local decisions without global coordination.
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The Biological Problem: SOP Selection

  • The Context: During the development of the fly, groups of identical cells must decide which will become sensory organs (SOPs).
  • The Dilemma: Any cell can be a leader, but neighboring cells cannot both be selected. There is no central controller.
  • The Mechanism: "Lateral Inhibition" — Each cell communicates only with its neighbors.
  • The Rule: Once a cell is selected, it inhibits all its neighbors.
  • The Result: An exact MIS pattern emerges naturally.
microscope style illustration of drosophila fly cells, some highlighted as special precursors (SOP) with spacing between them, biological diagram style
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Why Luby’s Algorithm Cannot Be Implemented by the Fly

Requires multi-bit communication

  • Luby: Priorities must be sent and compared → O(log n) bits
  • Fly: Cells use binary (on/off) signals

Requires identifying neighbors

  • Luby: Nodes must know which neighbor sent what
  • Fly: Cells cannot distinguish individual neighbors

➡️ Biological systems have much weaker communication capabilities

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How Symmetry Is Broken in the Fly

  • All cells start in the same state
  • Cells gradually increase their tendency to become SOP
  • Small random differences appear between neighboring cells
  • A cell that becomes slightly ahead inhibits its neighbors
  • Inhibition amplifies this difference and prevents neighbors from catching up
  • Outcome: A single SOP is selected from a symmetric group.
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From Biology to Algorithm

We translate the biological mechanism into computer science terms:
Biological ElementComputational Equivalent
CellProcessor / Node
Delta Protein1-bit Message
Lateral InhibitionNode becomes Inactive
SOP SelectionJoining the MIS
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The Rate Change Model

Traditional Problem:
Traditional algorithms need to know the number of neighbors (degree). Cells don't know their degree.
Biological Solution:
  • Start with a very low probability of speaking up.
  • Gradually increase the probability over time.
  • This avoids an initial 'shouting match' (collisions).
Chart
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Algorithm Steps

  • 1. Try Each node randomly decides whether to propose itself as a leader.
  • 2. Listen The node checks its neighbors: "Did anyone else propose?"
  • 3. Decide If the node is the sole volunteer (or wins the tie-break), it joins the independent set.

Selection Phase Visualization

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Table 1. MIS Algorithm

1.Algorithm: MIS (n, D) at node u
2.For i = 0: log D
3.    For j = 0: M log n // M is constant derived below
4.        * exchange 1 *
5.        v = 0
6.        With probability 1/2^(log D - i) broadcast B to neighbors and set v = 1
7.        If received message from neighbor, then v = 0
8.        * exchange 2 *
9.        If v = 1 then
10.            Broadcast B; join MIS; exit the algorithm
11.        Else
12.            If received message B in this exchange, then mark node u inactive; exit
13.    End
14. End
15. End
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Proof of Lemma 1
Lemma 1.
No two nodes in A (the output set) are connected to each other.
Proof:
  • A node w joins set A only if:
    • It broadcasts in Exchange 1, and
    • None of its neighbors broadcast in the same exchange.
  • When a node joins A:
    • All its neighbors are immediately marked inactive.
  • Therefore:
    • Two neighbors cannot join A in the same exchange.
    • If one joins earlier, the other becomes inactive.
Conclusion: No two neighboring nodes can both belong to A. ∎
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Lemma 2 (Maximality)
Lemma 2.
If node w exits the algorithm and it did not join A, then it is connected to a node in A.
Proof:
  • A node exits the algorithm only if:
    • It joins the MIS, or
    • It receives a broadcast from a neighbor and becomes inactive.
  • In the latter case (inactive):
    • The broadcasting neighbor definitely joins the MIS.
Conclusion: Every node not in the MIS is adjacent to a node in the MIS. ∎
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Lemma 3 (Efficiency)
Lemma 3:
If node w is in A, then all neighbors of w become inactive.
Proof:
  • By Lemma 1, we know that none of w's neighbors are in A.
  • By the code (Exchange 2), when w joins A:
    • It broadcasts to all its neighbors.
    • These neighbors then become inactive and exit.
Conclusion: w eliminates all its neighbors. ∎
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Lemma 4 (Degree Reduction Lemma)
Lemma 4.
With probability at least 1 − i/n2, by the end of phase i, there are no nodes with degree greater than D/2i.
Proof (Induction on i):
Base Case (i = 0)
  • For i = 0, the claim holds trivially, since D is an upper bound on the number of neighbors of any node.
Induction Hypothesis
  • Assume that by the end of phase i − 1, with probability at least 1 − (i−1)/n2, there are no nodes with more than 2D/2i active neighbors.
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Lemma 4: Induction Step
  • If no nodes have degree > D/2i at start of phase i, claim holds.
  • Otherwise, let v be a node with degree > D/2i.
  • During phase i, broadcast probability is p = 1/(D/2i).
Probability of a Broadcast
  • Prob(v or neighbors broadcast) ≥ 1 − 1/e.
Collision-Free Broadcast
  • Max neighbors is 2D/2i (by Hypothesis).
  • Thus, probability of no collision is bounded by a constant.
Therefore, in each step, v has a constant probability of being removed.
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Lemma 4: Conclusion
Multiple Steps in a Phase
  • Phase i consists of M log n steps.
  • Probability that node v is not removed is at most:
    (1 − c)M log n ≤ 1/n2
Union Bound
  • There are at most n nodes with degree > D/2i.
  • By a union bound, the probability that any such node remains is at most 1/n2.
Thus, with probability at least 1 − i/n2, there are no nodes with degree greater than D/2i at the end of phase i. ∎
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Theorem (Main Result)

Theorem.
With high probability, the distributed algorithm outputs a Maximal Independent Set (MIS).
Moreover:
  • Runs in polylogarithmic time
  • Uses only local communication
  • Requires no global knowledge of the network
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Complexity Analysis

⏱️ Time Complexity

  • Algorithm runs in O(log² n) rounds
  • There are O(log D) phases
  • Each phase has O(log n) steps
➡️ Total: O(log D · log n) = O(log² n)

📩 Message Complexity

  • Sends constant-size messages (1 bit)
  • Messages sent only to neighbors
  • Total complexity is polylogarithmic per node
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Summary

• MIS is a fundamental coordination problem
• Deterministic solutions fail (symmetry)
• Biology inspires a probabilistic algorithm
• Algorithm is correct, fast, and scalable
"Local randomness can replace global control."
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Thank You

Any Questions?

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MIS Algorithm: From Biological Inspiration to Computation

Explore how the fruit fly's SOP selection inspires efficient distributed Maximal Independent Set (MIS) algorithms for wireless networks and processors.

Maximal Independent Set (MIS): From Biology to Computation

Presenters: Leen Hassan, Yaman Dahle

Presentation Roadmap

1. Define the MIS Problem (Why it matters)<br>2. Explore the Biological Inspiration<br>3. Present the Formal Algorithm<br>4. Prove Correctness via Lemmas<br>5. Analyze Complexity & Conclude

Define the MIS Problem

Explore Biological Inspiration

Present the Formal Algorithm

Prove Correctness (Lemmas)

Analyze Complexity

Why MIS Matters?

• It creates a 'backbone' for wireless networks.<br>• Essential for efficient message routing.<br>• Allows clustering: selecting local leaders without a central authority.<br>• Vital for scalable ad-hoc sensor networks.

Informal Problem Definition

<b>The Setting: A Distributed System</b><br> • Processors solve a task jointly without global knowledge.<br> • Communication is strictly local (immediate neighbors only).<br><br> <b>The Goal: A Maximal Independent Set (MIS)</b><br> Select a subset of processors such that:<br> 1. <b>Independence:</b> No two neighboring processors are selected.<br> 2. <b>Dominance:</b> Every processor is either selected or adjacent to a selected one.

Formal Definition of MIS

Given a Graph G = (V, E), a subset A ⊆ V is a Maximal Independent Set if:<br><br>1. ∀ u, v ∈ A, (u, v) ∉ E<br> (No two nodes in A are neighbors)<br><br>2. ∀ v ∉ A, ∃ u ∈ A s.t. (u, v) ∈ E<br> (Every node outside A has a neighbor in A)

The Greedy Algorithm Approach

• Standard sequential method: Pick a node, remove its neighbors, repeat.<br>• <b>Problem:</b> In a distributed system, we don't have global vision.<br>• We need a parallel solution where nodes decide locally.

1. <b>Pick</b> an arbitrary node.<br>2. <b>Add</b> it to the Independent Set.<br>3. <b>Remove</b> it and all its neighbors.<br>4. <b>Repeat</b> until the graph is empty.

In a <b>distributed system</b>, we lack global knowledge.<br>Nodes cannot see the whole graph to "pick" sequentially.<br>We need a <b>local, parallel</b> strategy.

Luby’s Algorithm (1986)

• Each node chooses a random priority.<br>• A node joins the MIS if its priority is higher than all its neighbors’.<br>• All neighbors of a selected node become inactive.<br>• Repeat on the remaining nodes.

• <b>Randomness breaks symmetry.</b><br>• Terminates in O(log n) rounds with high probability.<br>• Correct and efficient in distributed networks.

Why is Distributed MIS Hard?

It requires <b>Symmetry Breaking</b>.<br><br>If all identical nodes try to become leaders at the same time, they collide.<br><br>If they wait for each other, it becomes too slow.<br><br>They must decide randomly, but efficiently.

The Challenge: Symmetry Breaking

<li style="margin-bottom: 15px;">In a distributed system, identical nodes lack a central coordinator.</li><li style="margin-bottom: 15px;">If they all act at once, they <b>collide</b>. If they all wait, they <b>deadlock</b>.</li><li style="margin-bottom: 15px;">They cannot simply "take turns" without communication.</li>

The Solution: Randomization

<li style="margin-bottom: 15px;">Nodes determine their actions by flipping a coin.</li><li style="margin-bottom: 15px;">Randomization breaks the symmetry naturally.</li><li style="margin-bottom: 15px;">It allows fast local decisions without global coordination.</li>

The Biological Problem: SOP Selection

<li style="margin-bottom: 20px;"><b>The Context:</b> During the development of the fly, groups of identical cells must decide which will become sensory organs (SOPs).</li><li style="margin-bottom: 20px;"><b>The Dilemma:</b> Any cell can be a leader, but neighboring cells cannot both be selected. There is no central controller.</li><li style="margin-bottom: 20px;"><b>The Mechanism:</b> "Lateral Inhibition" — Each cell communicates only with its neighbors.</li><li style="margin-bottom: 20px;"><b>The Rule:</b> Once a cell is selected, it inhibits all its neighbors.</li><li style="margin-bottom: 20px;"><b>The Result:</b> An exact MIS pattern emerges naturally.</li>

Why Luby’s Algorithm Cannot Be Implemented by the Fly

➡️ Biological systems have much weaker communication capabilities

How Symmetry Is Broken in the Fly

<ul style='list-style-type: disc; padding-left: 40px;'> <li style='margin-bottom: 30px;'>All cells start in the same state</li> <li style='margin-bottom: 30px;'>Cells gradually increase their tendency to become SOP</li> <li style='margin-bottom: 30px;'>Small random differences appear between neighboring cells</li> <li style='margin-bottom: 30px;'>A cell that becomes slightly ahead inhibits its neighbors</li> <li style='margin-bottom: 30px;'>Inhibition amplifies this difference and prevents neighbors from catching up</li> <li style='margin-bottom: 30px; font-weight:bold; color:#1e40af;'>Outcome: A single SOP is selected from a symmetric group.</li> </ul>

From Biology to Algorithm

We translate the biological mechanism into computer science terms:

<table style='width:100%; border-collapse:collapse; font-size:45px; margin-top:40px;'> <tr style='background-color:#34495e; color:white;'><th style='padding:20px; text-align:left;'>Biological Element</th><th style='padding:20px; text-align:left;'>Computational Equivalent</th></tr> <tr style='background-color:#ecf0f1;'><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>Cell</td><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>Processor / Node</td></tr> <tr style='background-color:#ffffff;'><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>Delta Protein</td><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>1-bit Message</td></tr> <tr style='background-color:#ecf0f1;'><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>Lateral Inhibition</td><td style='padding:20px; border-bottom:2px solid #bdc3c7;'>Node becomes Inactive</td></tr> <tr style='background-color:#ffffff;'><td style='padding:20px;'>SOP Selection</td><td style='padding:20px;'>Joining the MIS</td></tr> </table>

The Rate Change Model

<div style="margin-bottom: 40px;"> <strong>Traditional Problem:</strong><br> Traditional algorithms need to know the number of neighbors (degree). <span style="color:#C62828;">Cells don't know their degree.</span> </div> <div style="padding-left: 20px; border-left: 6px solid #1565C0;"> <strong style="color:#1565C0; display:block; margin-bottom:15px;">Biological Solution:</strong> <ul style="list-style-type: none; padding: 0; margin: 0;"> <li style="margin-bottom: 20px; display:flex; align-items:start;"><span style="color:#1565C0; margin-right:15px; font-size:40px;">•</span> Start with a very low probability of speaking up.</li> <li style="margin-bottom: 20px; display:flex; align-items:start;"><span style="color:#1565C0; margin-right:15px; font-size:40px;">•</span> Gradually increase the probability over time.</li> <li style="margin-bottom: 0px; display:flex; align-items:start;"><span style="color:#1565C0; margin-right:15px; font-size:40px;">•</span> This avoids an initial 'shouting match' (collisions).</li> </ul> </div>

The Algorithm in Action

Nodes broadcast randomly. If they speak alone, they join MIS (Blue). Their neighbors hear them and exit (Gray).

<ul style="list-style: none; padding: 0;"> <li style="margin-bottom: 50px;"> <strong style="color: #0e2a47; font-size: 55px; display: block; margin-bottom: 15px;">1. Try</strong> <span style="color:#333; font-size: 45px;">Each node randomly decides whether to propose itself as a leader.</span> </li> <li style="margin-bottom: 50px;"> <strong style="color: #0e2a47; font-size: 55px; display: block; margin-bottom: 15px;">2. Listen</strong> <span style="color:#333; font-size: 45px;">The node checks its neighbors: "Did anyone else propose?"</span> </li> <li style="margin-bottom: 50px;"> <strong style="color: #0e2a47; font-size: 55px; display: block; margin-bottom: 15px;">3. Decide</strong> <span style="color:#333; font-size: 45px;">If the node is the sole volunteer (or wins the tie-break), it joins the independent set.</span> </li> </ul>

Table 1. MIS Algorithm

1. Algorithm: MIS (n, D) at node u 2. For i = 0: log D 3. For j = 0: M log n // M is constant derived below 4. * exchange 1* 5. v = 0 6. With probability 1/2^(log D - i) broadcast B to neighbors and set v = 1 7. If received message from neighbor, then v = 0 8. * exchange 2 * 9. If v = 1 then 10. Broadcast B; join MIS; exit the algorithm 11. Else 12. If received message B in this exchange, then mark node u inactive; exit 13. End 14. End 15. End

Proof of Lemma 1

<b>Lemma 1:</b> No two nodes in A are connected to each other.

<b>Proof:</b> Node w joins set A if it broadcast at an exchange of type 1 and none of its neighbors broadcasts at the same exchange. This means that none of its neighbors has joined A in a previous step since when a node joins A all its neighbors are marked inactive in the exchange in which it joins A. Thus two neighboring nodes cannot join A at the same exchange, and when the earlier of them joins, the other one is marked inactive and will never join A. ■

<b>Lemma 1.</b><br>No two nodes in <b>A</b> (the output set) are connected to each other.

<div style="margin-left: 20px;"> <div style="margin-bottom:20px; font-weight:bold; color:#000000;">Proof:</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0;"> <li style="margin-bottom:15px; color:#000000;">A node <b>w</b> joins set <b>A</b> only if: <ul style="list-style-type: circle; padding-left: 50px; margin-top:10px; color:#222222;"> <li>It broadcasts in Exchange 1, and</li> <li>None of its neighbors broadcast in the same exchange.</li> </ul> </li> <li style="margin-bottom:15px; color:#000000;">When a node joins <b>A</b>: <ul style="list-style-type: circle; padding-left: 50px; margin-top:10px; color:#222222;"> <li>All its neighbors are immediately marked inactive.</li> </ul> </li> <li style="margin-bottom:15px; color:#000000;">Therefore: <ul style="list-style-type: circle; padding-left: 50px; margin-top:10px; color:#222222;"> <li>Two neighbors cannot join <b>A</b> in the same exchange.</li> <li>If one joins earlier, the other becomes inactive.</li> </ul> </li> </ul> <div style="margin-top:40px; border-top: 3px solid #000000; padding-top:20px; font-weight:bold; color:#000000;"> Conclusion: No two neighboring nodes can both belong to <b>A</b>. ∎ </div> </div>

Lemma 2 (Maximality)

<b>Lemma 2:</b> If node w exits the algorithm and it did not join A, then it is connected to a node in A.

<b>Proof:</b> This can only happen if node w executes the "then" part in Line 12 of the code.<br>This occurs only upon receiving a message from a neighboring node that has just joined A. ■

<b>Lemma 2.</b><br>If node w exits the algorithm and it did not join A, then it is connected to a node in A.

<div style="margin-left: 20px;"> <div style="margin-bottom:20px; font-weight:bold; color:#000000;">Proof:</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0;"> <li style="margin-bottom:30px; color:#000000;">A node exits the algorithm only if: <ul style="list-style-type: circle; padding-left: 50px; margin-top:15px; color:#222222;"> <li>It joins the MIS, or</li> <li>It receives a broadcast from a neighbor and becomes inactive.</li> </ul> </li> <li style="margin-bottom:30px; color:#000000;">In the latter case (inactive): <ul style="list-style-type: circle; padding-left: 50px; margin-top:15px; color:#222222;"> <li>The broadcasting neighbor definitely joins the MIS.</li> </ul> </li> </ul> <div style="margin-top:50px; border-top: 3px solid #000000; padding-top:30px; font-weight:bold; color:#000000;"> Conclusion: Every node not in the MIS is adjacent to a node in the MIS. ∎ </div> </div>

Lemma 3 (Efficiency)

<b>Lemma 3:</b> If w is in A then all the neighbors of w become inactive.

<b>Proof:</b> By lemma 1 we know that none of w's neighbors is in A. By the code (exchange 2) when w joins A it broadcasts to all its neighbors that then become inactive and exit the algorithm (Line 12). ■

<b>Lemma 3:</b><br>If node w is in A, then all neighbors of w become inactive.

<div style="margin-left: 20px;"> <div style="margin-bottom:20px; font-weight:bold; color:#000000;">Proof:</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0;"> <li style="margin-bottom:30px; color:#000000;">By <b>Lemma 1</b>, we know that none of w's neighbors are in A.</li> <li style="margin-bottom:30px; color:#000000;">By the code (Exchange 2), when w joins A: <ul style="list-style-type: circle; padding-left: 50px; margin-top:15px; color:#222222;"> <li>It broadcasts to all its neighbors.</li> <li>These neighbors then become inactive and exit.</li> </ul> </li> </ul> <div style="margin-top:50px; border-top: 3px solid #000000; padding-top:30px; font-weight:bold; color:#000000;"> Conclusion: w eliminates all its neighbors. ∎ </div> </div>

<ul style="margin:0; padding-left:40px; list-style-type: disc;"> <li style="margin-bottom:20px;">By <b>Lemma 1</b>, we know that none of <b>w</b>'s neighbors are in <b>A</b>.</li> <li style="margin-bottom:20px;">By the code (Exchange 2), when <b>w</b> joins <b>A</b>, it broadcasts to all its neighbors.</li> <li>Consequently, these neighbors become inactive and exit the algorithm. ■</li> </ul>

Lemma 4 (Degree Reduction Lemma)

<b>Lemma 4:</b> With probability at least (1 - i/n²) there are no nodes with degree > D/2^i at the end of phase i.

<b>Proof Overview:</b> By induction on i. Base i=0 is trivial. For the step, assume correctness for i-1. In phase i, the broadcast probability is tuned such that nodes with high degree are very likely to be removed (either joining A or neighbors joining A). This leads to a low probability of collision and high probability of degree reduction. (See supplementary material p.16 for full inductive math). ■

<b>Lemma 4.</b><br>With probability at least 1 − i/n<sup>2</sup>, by the end of phase i, there are no nodes with degree greater than D/2<sup>i</sup>.

<div style="margin-left: 20px;"> <div style="margin-bottom:20px; font-weight:bold; color:#000000;">Proof (Induction on i):</div> <div style="margin-bottom:15px; font-weight:bold; color:#000000; text-decoration: underline;">Base Case (i = 0)</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0; margin-bottom:20px;"> <li style="color:#000000;">For i = 0, the claim holds trivially, since D is an upper bound on the number of neighbors of any node.</li> </ul> <div style="margin-bottom:15px; font-weight:bold; color:#000000; text-decoration: underline;">Induction Hypothesis</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0;"> <li style="color:#000000;">Assume that by the end of phase i − 1, with probability at least 1 − (i−1)/n<sup>2</sup>, there are no nodes with more than 2D/2<sup>i</sup> active neighbors.</li> </ul> </div>

Lemma 4: Induction Step

<div style="margin-left: 20px; font-size: 42px; line-height: 1.6;"> <ul style="list-style-type: disc; padding-left: 50px; margin:0;"> <li style="margin-bottom:35px; color:#000000;">If no nodes have degree > D/2<sup>i</sup> at start of phase i, claim holds.</li> <li style="margin-bottom:35px; color:#000000;">Otherwise, let v be a node with degree > D/2<sup>i</sup>.</li> <li style="margin-bottom:35px; color:#000000;">During phase i, broadcast probability is p = 1/(D/2<sup>i</sup>).</li> </ul> <div style="margin-top:40px; font-weight:bold; color:#000000; margin-bottom:20px;">Probability of a Broadcast</div> <ul style="list-style-type: circle; padding-left: 50px; margin:0; margin-bottom:35px;"> <li style="color:#222; margin-bottom:15px;">Prob(v or neighbors broadcast) ≥ 1 − 1/e.</li> </ul> <div style="font-weight:bold; color:#000000; margin-bottom:20px;">Collision-Free Broadcast</div> <ul style="list-style-type: circle; padding-left: 50px; margin:0; margin-bottom:35px;"> <li style="color:#222; margin-bottom:15px;">Max neighbors is 2D/2<sup>i</sup> (by Hypothesis).</li> <li style="color:#222;">Thus, probability of no collision is bounded by a constant.</li> </ul> <div style="border-top: 3px solid #000; padding-top:20px; margin-top:30px; font-weight:bold;"> Therefore, in each step, v has a constant probability of being removed. </div> </div>

Lemma 4: Conclusion

<div style="margin-left: 20px; font-size: 42px; line-height: 1.6;"> <div style="font-weight:bold; color:#000000; margin-bottom:20px;">Multiple Steps in a Phase</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0; margin-bottom:40px;"> <li style="margin-bottom:35px; color:#000000;">Phase i consists of M log n steps.</li> <li style="margin-bottom:35px; color:#000000;">Probability that node v is not removed is at most:<br> (1 − c)<sup>M log n</sup> ≤ 1/n<sup>2</sup></li> </ul> <div style="font-weight:bold; color:#000000; margin-bottom:20px;">Union Bound</div> <ul style="list-style-type: disc; padding-left: 50px; margin:0; margin-bottom:40px;"> <li style="margin-bottom:35px; color:#000000;">There are at most n nodes with degree > D/2<sup>i</sup>.</li> <li style="margin-bottom:35px; color:#000000;">By a union bound, the probability that any such node remains is at most 1/n<sup>2</sup>.</li> </ul> <div style="margin-top:40px; border-top: 3px solid #000000; padding-top:30px; font-weight:bold; color:#000000;"> Thus, with probability at least 1 − i/n<sup>2</sup>, there are no nodes with degree greater than D/2<sup>i</sup> at the end of phase i. ∎ </div> </div>

Theorem (Main Result)

<b>Theorem 1:</b> With probability 1 - (log D)/n², all nodes are either in A or connected to a node in A by the end of the algorithm.

Using Lemma 4, by the end of phase log D, remaining nodes have degree of 0 relative to active nodes (they have no active neighbors). These nodes will join A with no collisions. Lemma 3 ensures they have no neighbors already in A. Thus, a valid MIS is formed.

With high probability, the distributed algorithm outputs a Maximal Independent Set (MIS).

<div style='font-weight:bold; margin-bottom:30px; color:#000000;'>Moreover:</div> <ul style='list-style:none; padding:0; margin:0;'> <li style='margin-bottom:30px; padding-left: 40px; position: relative;'> <span style='position: absolute; left: 0; color: #0047AB; font-weight: bold;'>•</span> Runs in <strong>polylogarithmic time</strong> </li> <li style='margin-bottom:30px; padding-left: 40px; position: relative;'> <span style='position: absolute; left: 0; color: #0047AB; font-weight: bold;'>•</span> Uses only <strong>local communication</strong> </li> <li style='margin-bottom:30px; padding-left: 40px; position: relative;'> <span style='position: absolute; left: 0; color: #0047AB; font-weight: bold;'>•</span> Requires <strong>no global knowledge</strong> of the network </li> </ul>

Complexity Analysis

<b>Time Complexity:</b><br>O(log D · log n). Since D ≤ n, it is O(log² n).<br><br><b>Message Complexity:</b><br>Expected number of messages is linear in the number of nodes (O(n)).<br>This is optimal.<br>Messages are only 1-bit (Beep).

⏱️ Time Complexity

<ul style="margin:0; padding-left:40px; list-style-type:disc;"> <li style="margin-bottom:15px;">Algorithm runs in <b>O(log² n)</b> rounds</li> <li style="margin-bottom:15px;">There are <b>O(log D)</b> phases</li> <li style="margin-bottom:15px;">Each phase has <b>O(log n)</b> steps</li> </ul> <div style="margin-top:25px; font-weight:bold; color:#0056b3;"> ➡️ Total: O(log D · log n) = O(log² n) </div>

📩 Message Complexity

<ul style="margin:0; padding-left:40px; list-style-type:disc;"> <li style="margin-bottom:15px;">Sends <b>constant-size messages</b> (1 bit)</li> <li style="margin-bottom:15px;">Messages sent <b>only to neighbors</b></li> <li>Total complexity is <b>polylogarithmic</b> per node</li> </ul>

Summary

Following the nature of the fruit fly, we derived an efficient algorithm for the MIS problem.<br><br>• No need to know neighbor count.<br>• Minimal communication (1-bit).<br>• Optimal Message Complexity.<br>• Demonstrated similarity between Biological and Computational efficiency.

MIS is a fundamental coordination problem

Deterministic solutions fail (symmetry)

Biology inspires a probabilistic algorithm

Algorithm is correct, fast, and scalable

Local randomness can replace global control.

Thank You

Any Questions?

  • mis-algorithm
  • distributed-systems
  • biology-inspired-computing
  • maximal-independent-set
  • symmetry-breaking
  • algorithm-complexity
  • wireless-networks